Question 394: Centre of Mass and Rotational Motion

Question

A solid sphere with uniform density and radius $R$ is rotating initially with constant angular velocity $\left(\omega_1\right)$ about its diameter. After some time during the rotation its starts loosing mass at a uniform rate, with no change in its shape. The angular velocity of the sphere when its radius become $\mathrm{R} / 2$ is $x \omega_1$. The value of $x$ is _________.

Accepted Answer

When sphere is of radius $R$, its mass is $M$, when radius is reduced to $\frac{R}{2}$, mass will reduced to $\frac{M}{8}$
Now by conservation of angular momentum
$$\begin{aligned}
& \left(	au_{\mathrm{ext}}=0ight) \
& \mathrm{L}_1=\mathrm{L}_2 \
& \mathrm{I}_1 \omega_1=\mathrm{I}_2 \omega_2 \
& \left(\frac{2}{5} \mathrm{MR}^2ight) \omega_1=\left(\frac{2}{5}\left(\frac{\mathrm{M}}{8}ight)\left(\frac{\mathrm{R}}{2}ight)^2ight) \omega_2
\end{aligned}$$
$\omega_2=32 \omega_1 \quad$ value of x is 32
Answer is 32

Centre of Mass and Rotational Motion

Integer / Numeric Answer Type