Question 473: Atoms & Nuclei

Question

The energy levels with transitions for the atom are shown. The transitions corresponding to emission of radiation of maximum and minimum wavelength are respectively
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Accepted Answer

As, we know that the difference of energy between two level is equal to the energy of photon.
$\begin{aligned}
& \Delta E=h v=\frac{h c}{\lambda} \Rightarrow \lambda=\frac{h c}{\Delta E} \
	ext{or}\quad& \lambda \propto \frac{1}{\Delta E}
\end{aligned}$
The value of $\Delta E$ is minimum for $A$, so radiation corresponding to $A$ have maximum wavelength and value of $\Delta E$ is maximum for $D$, so radiation corresponding to $D$ have minimum wavelength.

Answer

B, C

Answer

A, C

Answer

C, D

Answer

A, D

Atoms & Nuclei

The energy levels with transitions for the atom are shown. The transitions corresponding to emission of radiation of maximum and minimum wavelength are respectively

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