Question 232: Atoms & Nuclei

Question

A He
+
ion is in its first excited state. Its
ionization energy is :-

Accepted Answer

$$T.E. =  - \left( {13.6} \right)\left( {{{{Z^2}} \over {{n^2}}}} \right)eV$$
z = n = 2
$$ \Rightarrow $$ Ionisation energy = Ã¢ÂÂT.E.
= 13.6 eV

Answer

13.60 eV

Answer

6.04 eV

Answer

48.36 eV

Answer

54.40 eV

Atoms & Nuclei