Question 599: Atoms & Nuclei

Question

A sample of radioactive element containing 4 $ 	imes $ 10
16
active nuclei. Half life of element is 10 days, then number of decayed nuclei after 30 days

Accepted Answer

N = 4 $ 	imes $ 10
16
${\left( {{1 \over 2}} ight)^{{{30} \over {10}}}}$ = ${1 \over 2}$ $ 	imes $ 10
16
$ 	herefore $ Atoms decayed = 4 $ 	imes $ 10
16
- ${1 \over 2}$ $ 	imes $ 10
16
= 3.5 $ 	imes $ 10
16

Answer

0.5 $ 	imes $ 10
16

Answer

2 $ 	imes $ 10
16

Answer

3.5 $ 	imes $ 10
16

Answer

1 $ 	imes $ 10
16

Atoms & Nuclei

A sample of radioactive element containing 4 \times 10 16 active nuclei. Half life of element is 10 days, then number of decayed nuclei after 30 days

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