Question 549: Atoms & Nuclei

Question

The power obtained in a reactor using U
235
disintegration is 1000 kW. The mass decay of U
235
per hour is

Accepted Answer

From Einstein relation, E = mc
2
Rearranging, m = ${E \over {{c^2}}}$
We see that mass decay per second :
${{dm} \over {dt}}$ = ${1 \over {{c^2}}}$
 ÃÂ ${{dE} \over {dt}}$ = ${{1000 	imes {{10}^3}} \over {{{\left( {3 	imes {{10}^8}} ight)}^2}}}$
Now mass decay of U
235
per hour,
= ${{dm} \over {dt}}$ $ 	imes $ 60 $ 	imes $ 60
= ${{1000 	imes {{10}^3}} \over {{{\left( {3 	imes {{10}^8}} ight)}^2}}}$ $ 	imes $ 3600
= 4 ÃÂ 10
Ã¢ÂÂ8
kg = 40 microgram

Answer

10 microgram

Answer

20 microgram

Answer

40 microgram

Answer

1 microgram

Atoms & Nuclei

The power obtained in a reactor using U 235 disintegration is 1000 kW. The mass decay of U 235 per hour is

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