Question 125: Atoms & Nuclei

Question

If the wavelength of the first member of Lyman series of hydrogen is $\lambda$. The wavelength of the second member will be

Accepted Answer

$\begin{aligned}
& \frac{1}{\lambda}=\frac{13.6 \mathrm{z}^2}{\mathrm{hc}}\left[\frac{1}{1^2}-\frac{1}{2^2}ight] ...... 	ext{(i)}\
& \frac{1}{\lambda^{\prime}}=\frac{13.6 \mathrm{z}^2}{\mathrm{hc}}\left[\frac{1}{1^2}-\frac{1}{3^2}ight] ...... 	ext{(ii)}
\end{aligned}$
On dividing (i) & (ii)
$\lambda^{\prime}=\frac{27}{32} \lambda$

Answer

$\frac{27}{5} \lambda$

Answer

$\frac{5}{27} \lambda$

Answer

$\frac{27}{32} \lambda$

Answer

$\frac{32}{27} \lambda$

Atoms & Nuclei

If the wavelength of the first member of Lyman series of hydrogen is \lambda. The wavelength of the second member will be

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