Question 180: AC fundamentals

Question

In an oscillating $$LC$$ circuit the maximum charge on the capacitor is $$Q$$. The charge on the capacitor when the energy is stored equally between the electric and magnetic field is

Accepted Answer

When the capacitor is completely charged, the total energy in the $$L.C$$ circuit is with the capacitor and that energy is $$E = {1 \over 2}{{{Q^2}} \over C}$$
When half energy is with the capacitor in the form of electric field between the plates of the capacitor we get 
$${E \over 2} = {1 \over 2}{{Q{'^2}} \over C}$$ where $$Q'$$ is the charge on plate of the capacitor
$$	herefore$$ $${1 \over 2} 	imes {1 \over 2}{{{Q^2}} \over C} = {1 \over 2}{{Q{'^2}} \over C}$$
$$ \Rightarrow Q' = {Q \over {\sqrt 2 }}$$

Answer

$${Q \over 2}$$

Answer

$${Q \over {\sqrt 3 }}$$

Answer

$${Q \over {\sqrt 2 }}$$

Answer

$$Q$$

AC fundamentals

In an oscillating $LC circuit the maximum charge on the capacitor is Q$. The charge on the capacitor when the energy is stored equally between the electric and magnetic field is

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