Question 352: AC fundamentals

Question

In an oscillating LC circuit, the maximum charge on the capacitor is '$Q$'. When the energy is stored equally between the electric and magnetic fields, the charge on the capacitor becomes

Accepted Answer

Maximum energy stored in a capacitor,
$\mathrm{E}_1=\frac{\mathrm{Q}^2}{2 \mathrm{C}}$
When energy is stored equally between the electric and magnetic fields, then energy in the capacitor is $\mathrm{E}_2=\frac{1}{2} \mathrm{E}_1$
If $\mathrm{Q}^{\prime}$ is the charge on the capacitor in this case, then $\mathrm{E}_2=\frac{\mathrm{Q}^{\prime 2}}{2 \mathrm{C}}$.
$\begin{aligned}
	herefore \quad & \frac{\mathrm{Q}^{\prime 2}}{2 \mathrm{C}}=\frac{1}{2} \frac{\mathrm{Q}^2}{2 \mathrm{C}} \
\mathrm{Q}^{\prime} & =\frac{\mathrm{Q}}{\sqrt{2}}.
\end{aligned}$

Answer

$\frac{\mathrm{Q}}{4}$

Answer

$\mathrm{\frac{Q}{2}}$

Answer

$\frac{\mathrm{Q}}{\sqrt{2}}$

Answer

$\frac{\mathrm{Q}}{\sqrt{3}}$

AC fundamentals

In an oscillating LC circuit, the maximum charge on the capacitor is 'Q'. When the energy is stored equally between the electric and magnetic fields, the charge on the capacitor becomes

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