Question 438: AC fundamentals

Question

The magnetic energy stored in an inductor of inductance $$4 ~\mu \mathrm{H}$$ carrying a current of $$2 \mathrm{~A}$$ is :

Accepted Answer

The formula for calculating the magnetic energy stored in an inductor is given by:
$$E = \frac{1}{2} L I^2$$
where:
$$E$$ is the energy stored (in joules, J),
$$L$$ is the inductance of the inductor (in henrys, H),
$$I$$ is the current flowing through the inductor (in amperes, A).
Plugging the given values into the formula:
$$E = \frac{1}{2} 	imes 4 \mu H 	imes (2 A)^2$$
$$E =\frac{1}{2} 	imes 4 	imes 10^{-6} H 	imes 4 A^2$$
$$E = 2 	imes 10^{-6} H \cdot 4$$
$$E = 8 	imes 10^{-6} J$$
Hence, the energy stored in the inductor is $$8 \mu J$$.

Answer

$$4 \mathrm{~mJ}$$

Answer

$$8 \mathrm{~mJ}$$

Answer

$$8 ~\mu \mathrm{J}$$

Answer

$$4 ~\mu \mathrm{J}$$

AC fundamentals

The magnetic energy stored in an inductor of inductance $4 ~\mu \mathrm{H} carrying a current of 2 \mathrm{~A}$ is :

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