Question 402: AC fundamentals

Question

In an a.c. circuit, a resistance R = 40 $\Omega$ and an inductance 'L' are connected in series. If the phase angle between voltage and current is 45$^\circ$, then the value of the inductive reactance is (tan 45$^\circ$ = 1)

Accepted Answer

In an AC circuit where a resistance $ R = 40 \ \Omega $ and an inductance $ L $ are connected in series, the phase angle $ \phi $ between the voltage and current is given as 45$^\circ$. We need to determine the inductive reactance $ X_L $.
The phase angle in an RL series circuit is given by the tangent of the angle:
$ 	an(\phi) = \frac{X_L}{R} $
Given $ \phi = 45^\circ $ and $ 	an 45^\circ = 1 $, we have:
$ 	an(45^\circ) = \frac{X_L}{R} = 1 $
Thus:
$ X_L = R $
Given $ R = 40 \ \Omega $, we find:
$ X_L = 40 \ \Omega $
Therefore, the value of the inductive reactance is 40$\Omega$ (Option B).

Answer

50$\Omega$

Answer

40$\Omega$

Answer

10$\Omega$

Answer

20$\Omega$

AC fundamentals

In an a.c. circuit, a resistance R = 40 \Omega and an inductance 'L' are connected in series. If the phase angle between voltage and current is 45^\circ, then the value of the inductive reactance is (tan 45^\circ = 1)

Choose the correct answer: