Question 406: AC fundamentals

Question

Three pure inductors each of inductance 6H are connected as shown in the figure. Their equivalent inductance between the points 'P' and 'Q' is
![](https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lnh117d4/1bef5c7e-ea84-428b-8179-bb27c6f7c2fd/f5570080-659b-11ee-a6ec-2bb503f151f3/file-6y3zli1lnh117d5.png?format=png)

Accepted Answer

In the given circuit, one end of each inductor is joined together. Similarly, the other end of each inductor is joined together. Hence the three inductors are connected in parallel. Their equivalent inductance is given by
$\begin{aligned}
& \frac{1}{L}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=\frac{3}{6} \
& 	herefore L=2 H
\end{aligned}$

Answer

0.5 H

Answer

18 H

Answer

6.3 H

Answer

2 H

AC fundamentals

Three pure inductors each of inductance 6H are connected as shown in the figure. Their equivalent inductance between the points 'P' and 'Q' is

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