Question 163: AC fundamentals

Question

In the circuit shown here, the  point $'C'$ is kept connected to point $'A'$ till the current flowing through the circuit becomes constant. Afterward, suddenly, point $'C'$ is disconnected from point $'A'$ and connected to point $'B'$ at time $t=0.$ Ratio of the voltage across resistance and the inductor at $t=L/R$ will be equal to :
![](https://imagex.cdn.examgoal.net/6Nn1GR8Yk6DtYaClG/x4cEjVsiSMGxerw41uW6xRzteS0e5/bkPdPlBRSFhyRFyLyhQzNG/image.png)

Accepted Answer

Applying kirchhoffs law of voltage in closed loop
$ - {V_R} - {V_C} = 0 \Rightarrow {{{V_R}} \over {{V_C}}} =  - 1$
![](https://imagex.cdn.examgoal.net/osxEA5W4HEwjH9oxi/UftgHtzseikiW4hHddnvBxk7XKEgG/jprULz3NC4qrZzQAgUIdwP/image.png)

Answer

${e \over {1 - e}}$

Answer

$1$

Answer

$-1$

Answer

${{1 - e} \over e}$

AC fundamentals

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