Question 123: AC fundamentals

Question

In a series LCR circuit, the inductive reactance (X
L
) is 10$$\Omega$$ and the capacitive reactance (X
C
) is 4$$\Omega$$. The resistance (R) in the circuit is 6$$\Omega$$. The power factor of the circuit is :

Accepted Answer

Given :
X
L
= 10$$\Omega$$
X
C
= 4$$\Omega$$
R = 6$$\Omega$$
$$ 	herefore $$ Power factor = cos$$	heta$$ = $${R \over Z}$$
$$ = {R \over {\sqrt {{R^2} + {{({X_L} - {X_C})}^2}} }}$$
$$ = {6 \over {\sqrt {{6^2} + {{(10 - 4)}^2}} }}$$
$$ = {6 \over {6\sqrt 2 }} = {1 \over {\sqrt 2 }}$$

Answer

$${1 \over 2}$$

Answer

$${{\sqrt 3 } \over 2}$$

Answer

$${1 \over {\sqrt 2 }}$$

Answer

$${1 \over {2\sqrt 2 }}$$

AC fundamentals

In a series LCR circuit, the inductive reactance (X L ) is 10$\Omega and the capacitive reactance (X C ) is 4\Omega. The resistance (R) in the circuit is 6\Omega$. The power factor of the circuit is :

Choose the correct answer: