Question 159: AC fundamentals

Question

A series
LR
circuit is connected to a voltage source with
V(t) = V
0
sin$$\Omega $$t. After very large time, current
I(t)
behaves as
(t
0
>> $${L \over R}$$) :

Accepted Answer

Current in LR circuit,
$${\rm I} = {{{V_0}} \over {\sqrt {{R^2} + {w^2}{L^2}} }}\sin \left( {\omega t - {\pi  \over 2}} \right)$$
it will be a sinusoidal wave.

Answer

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AC fundamentals

A series LR circuit is connected to a voltage source with V(t) = V 0 sin$\Omega t. After very large time, current I(t) behaves as (t 0 >> {L \over R}$) :

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