Question 446: AC fundamentals

Question

A capacitor of capacitance 'C', is connected across an ac source of voltage V, given by
V = V
0
sin$$\omega$$t
The displacement current between the plates of the capacitor, would then be given by :

Accepted Answer

Given, V = V
0
sin$$\omega$$t
We know, $$q = CV$$
Now displacement current I
d
is given by,
I
d
= $${{dq} \over {dt}} = {{CdV} \over {dt}}$$
$${I_d} = C({V_0}\omega \cos \omega t)$$
$$ = {V_0}\omega C\cos \omega t$$

Answer

$${I_d} = {V_0}\omega C\sin \omega t$$

Answer

$${I_d} = {V_0}\omega C\cos \omega t$$

Answer

$${I_d} = {{{V_0}} \over {\omega C}}\cos \omega t$$

Answer

$${I_d} = {{{V_0}} \over {\omega C}}\sin \omega t$$

AC fundamentals

A capacitor of capacitance 'C', is connected across an ac source of voltage V, given by V = V 0 sin$\omega$t The displacement current between the plates of the capacitor, would then be given by :

Choose the correct answer: