Question 107: Semiconductors and Logic Gates

Question

The correct relation between $$\alpha$$ (ratio of collector current to emitter current) and $$\beta$$ (ratio of collector current to base current) of a transistor is :

Accepted Answer

$$\alpha  = {{{I_C}} \over {{I_E}}}$$ & $$\beta  = {{{I_C}} \over {{I_B}}}$$ & $${I_E} = {I_B} + {I_C}$$
$$ 	herefore $$ $${{{I_E}} \over {{I_C}}} = {{{I_B}} \over {{I_C}}} + {{{I_C}} \over {{I_C}}}$$
$$ \Rightarrow {1 \over \alpha } = {1 \over \beta } + 1 = {{1 + \beta } \over \beta }$$
$$ \Rightarrow \alpha  = {\beta  \over {1 + \beta }}$$

Answer

$$\beta  = {\alpha  \over {1 + \alpha }}$$

Answer

$$\alpha  = {\beta  \over {1 - \alpha }}$$

Answer

$$\alpha  = {\beta  \over {1 + \beta }}$$

Answer

$$\beta  = {1 \over {1 - \alpha }}$$

Semiconductors and Logic Gates

The correct relation between $\alpha (ratio of collector current to emitter current) and \beta$ (ratio of collector current to base current) of a transistor is :

Choose the correct answer: