Question 98: Semiconductors and Logic Gates

Question

For a transistor $$\alpha$$ and $$\beta$$ are given as $$\alpha  = {{{I_C}} \over {{I_E}}}$$ and $$\beta  = {{{I_C}} \over {{I_B}}}$$. Then the correct relation between $$\alpha$$ and $$\beta$$ will be :

Accepted Answer

$$\alpha  = {{{I_C}} \over {{I_E}}}$$, $$\beta  = {{{I_C}} \over {{I_B}}}$$; $${I_E} = {I_C} + {I_B}$$
$$\alpha  = {{{I_C}} \over {{I_C} + {I_B}}} = {{{I_C}/{I_B}} \over {{{{I_C}} \over {{I_B}}} + 1}} = {\beta  \over {\beta  + 1}}$$
$$1 + {1 \over \beta } = {1 \over \alpha }$$
$${1 \over \beta } = {{1 - \alpha } \over \alpha }$$
$$\beta  = {\alpha  \over {1 - \alpha }}$$

Answer

$$\alpha  = {{1 - \beta } \over \beta }$$

Answer

$$\beta  = {\alpha  \over {1 - \alpha }}$$

Answer

$$\alpha \beta  = 1$$

Answer

$$\alpha  = {\beta  \over {1 - \beta }}$$

Semiconductors and Logic Gates

For a transistor $\alpha and \beta are given as \alpha = {{{I_C}} \over {{I_E}}} and \beta = {{{I_C}} \over {{I_B}}}. Then the correct relation between \alpha and \beta$ will be :

Choose the correct answer: