Question 54: Semiconductors and Logic Gates

Question

The output from NAND gate having inputs A and B given below will be,

Accepted Answer

$$
\begin{aligned}
&	ext {Truth table for NAND gate is }\\
&\begin{array}{|c|c|c|}
\hline \mathrm{A} & \mathrm{B} & \mathrm{Y}=\overline{\mathrm{A} \cdot \mathrm{B}} \
\hline 0 & 0 & 1 \
\hline 0 & 1 & 1 \
\hline 1 & 0 & 1 \
\hline 1 & 1 & 0 \
\hline
\end{array}
\end{aligned}
$$
On the basis of given input $\mathrm{A}$ and $\mathrm{B}$ the truth table is
$\mathrm{A}$
$\mathrm{B}$
$\mathrm{Y}$
1
1
0
0
0
1
0
1
1
1
0
1
1
1
0
0
0
1
0
1
1

Answer

Answer

Answer

Answer

Semiconductors and Logic Gates

The output from NAND gate having inputs A and B given below will be,

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