Question 230: Semiconductors and Logic Gates

Question

An npn transistor operates as a common emitter amplifier with a power gain of 106. The input circuit resistance is 100$$\Omega$$ and the output load resistance is 10 K$$\Omega$$. The common emitter current gain '$$\beta$$' will be ________. (Round off to the Nearest Integer).

Accepted Answer

Power gain = 10
6
Input resistance = 100$$\Omega$$
Output load resistance = 10K$$\Omega$$
Power gain = $${\beta^2} 	imes {{{r_{out}}} \over {{R_{in}}}}$$
$$ \Rightarrow $$ $${10^6} = {\beta ^2} 	imes {{10 	imes {{10}^3}} \over {100}}$$
$$ \Rightarrow $$ $$\beta$$
2
= 10
4
$$ \Rightarrow $$ $$\beta$$ = 100

Semiconductors and Logic Gates

An npn transistor operates as a common emitter amplifier with a power gain of 106. The input circuit resistance is 100$\Omega and the output load resistance is 10 K\Omega. The common emitter current gain '\beta$' will be ________. (Round off to the Nearest Integer).

Choose the correct answer: