Question 49: Semiconductors and Logic Gates

Question

The truth table for this given circuit is :

Accepted Answer

$$\begin{aligned}
\mathrm{Y} & =\mathrm{A} \cdot \mathrm{B}+\overline{\mathrm{A}} \cdot \mathrm{B} \
& =(\mathrm{A}+\overline{\mathrm{A}}) \cdot \mathrm{B} \
\mathrm{Y} & =1 \cdot \mathrm{B} \
\mathrm{Y} & =\mathrm{B}
\end{aligned}$$

Answer

Answer

Answer

Answer

Semiconductors and Logic Gates

The truth table for this given circuit is :

Choose the correct answer: