Question 56: Semiconductors and Logic Gates

Question

In an n-p-n common emitter (CE) transistor the collector current changes from 5 $$\mathrm{mA}$$ to $$16 \mathrm{~mA}$$ for the change in base current from $$100~ \mu \mathrm{A}$$ and $$200 ~\mu \mathrm{A}$$, respectively. The current gain of transistor is __________.

Accepted Answer

The current gain of a transistor in common emitter configuration is given by:
$$\beta = \frac{I_C}{I_B}$$
where $$I_C$$ is the collector current and $$I_B$$ is the base current.
In this case, the collector current changes from $$5 \mathrm{~mA}$$ to $$16 \mathrm{~mA}$$ for the change in base current from $$100~ \mu \mathrm{A}$$ to $$200 ~\mu \mathrm{A}$$. Therefore, we have:
$$\Delta I_C = 16 \mathrm{~mA} - 5 \mathrm{~mA} = 11 \mathrm{~mA}$$
$$\Delta I_B = 200~ \mu \mathrm{A} - 100~ \mu \mathrm{A} = 100~ \mu \mathrm{A}$$
Therefore, the current gain of the transistor is:
$$\beta = \frac{\Delta I_C}{\Delta I_B} = \frac{11 \mathrm{~mA}}{100~ \mu \mathrm{A}} = 110$$
Therefore, the current gain of the transistor is 110.

Answer

210

Answer

0.9

Answer

9

Answer

110

Semiconductors and Logic Gates

In an n-p-n common emitter (CE) transistor the collector current changes from 5 $\mathrm{mA} to 16 \mathrm{~mA} for the change in base current from 100~ \mu \mathrm{A} and 200 ~\mu \mathrm{A}$, respectively. The current gain of transistor is __________.

Choose the correct answer: