Question 5: Semiconductors and Logic Gates

Question

Identify the correct truth table of the given logic circuit

Accepted Answer

$y = A \cdot \overline{A \cdot B}$ $\$

$= A \cdot (\overline{A} + \overline{B}) = 0 + A\overline{B}$

Answer

$\begin{array}{|c|c|c|}
\hline
A & B & Y \
\hline
0 & 0 & 0 \
\hline
0 & 1 & 0 \
\hline
1 & 0 & 1 \
\hline
1 & 1 & 0 \
\hline
\end{array}$

Answer

$\begin{array}{|c|c|c|}
\hline
A & B & Y \
\hline
0 & 0 & 0 \
\hline
0 & 1 & 1 \
\hline
1 & 0 & 1 \
\hline
1 & 1 & 0 \
\hline
\end{array}$

Answer

$\begin{array}{|c|c|c|}
\hline
A & B & Y \
\hline
0 & 0 & 1 \
\hline
0 & 1 & 1 \
\hline
1 & 0 & 1 \
\hline
1 & 1 & 0 \
\hline
\end{array}$

Answer

$\begin{array}{|c|c|c|}
\hline
A & B & Y \
\hline
0 & 0 & 1 \
\hline
0 & 1 & 0 \
\hline
1 & 0 & 1 \
\hline
1 & 1 & 0 \
\hline
\end{array}$

Semiconductors and Logic Gates