Question 341: Atoms & Nuclei

Question

A radioactive sample at any instant has its disintegration rate $$5000$$ disintegrations per minute. After $$5$$ minutes, the rate is $$1250$$ disintegrations per minute. Then, the decay constant (per minute) is

Accepted Answer

$$\lambda  = {1 \over t}{\log _e}{{{A_0}} \over A}$$
$$ = {1 \over 5}{\log _e}{{5000} \over {1250}}$$
$$= 0.2{\log _e}4$$
$$ = 0.4{\log _e}2$$

Answer

$$0.4$$ $$ln2$$

Answer

$$0.2$$ $$ln2$$

Answer

$$0.1$$ $$ln2$$

Answer

$$0.8$$ $$ln2$$

Atoms & Nuclei

A radioactive sample at any instant has its disintegration rate $5000 disintegrations per minute. After 5 minutes, the rate is 1250$ disintegrations per minute. Then, the decay constant (per minute) is

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