Question 284: Atoms & Nuclei

Question

In a hydrogen like atom, when an electron jumps from the M-shell to the L-shell, the wavelength of emitted radiation is $$\lambda $$. If an electron jumps from N-shell to the L-shell, the wavelength of emitted radiation will be:

Accepted Answer

For M $$ 	o $$ L steel
$${1 \over \lambda }$$ = K $$\left( {{1 \over {{2^2}}} - {1 \over {{3^2}}}} ight) = {{K 	imes 5} \over {36}}$$
for  N $$ 	o $$  L
$${1 \over {\lambda '}}$$  = K$$\left( {{1 \over {{2^2}}} - {1 \over {{4^2}}}} ight) = {{K 	imes 3} \over {16}}$$
$$\lambda ' = {{20} \over {27}}\lambda $$

Answer

$${{25} \over {16}}$$ $$\lambda $$

Answer

$${{27} \over {20}}$$ $$\lambda $$

Answer

$${{16} \over {25}}$$ $$\lambda $$

Answer

$${{20} \over {27}}$$ $$\lambda $$

Atoms & Nuclei

In a hydrogen like atom, when an electron jumps from the M-shell to the L-shell, the wavelength of emitted radiation is $\lambda $. If an electron jumps from N-shell to the L-shell, the wavelength of emitted radiation will be:

Choose the correct answer: