Question 266: Atoms & Nuclei

Question

In a reactor, 2 kg of 92U235 fuel is fully used up
in 30 days. The energy released per fission is
200 MeV. Given that the Avogadro number,
N = 6.023 $$ 	imes $$ 1026 per kilo mole and 1 eV =
1.6 × 10–19 J. The power output of the reactor is
close to

Accepted Answer

Number of uranium atoms in 2 kg
= $${{2 	imes 6.023 	imes {{10}^{26}}} \over {235}}$$
Energy from one atom is 200 ÃÂ 10
6
e.V. hence total energy from 2 kg uranium
= $${{2 	imes 6.023 	imes {{10}^{26}}} \over {235}} 	imes 200 	imes {10^6}$$ eV
= $${{2 	imes 6.023 	imes {{10}^{26}}} \over {235}} 	imes 200 	imes {10^6}$$ $$ 	imes $$ 1.6 ÃÂ 10
Ã¢ÂÂ19
J
2 kg uranium is used in 30 days  hence energy received per second or
power is
Power = $${{2 	imes 6.023 	imes {{10}^{26}} 	imes 200 	imes {{10}^6} 	imes 1.6 	imes {{10}^{ - 19}}} \over {235 	imes 30 	imes 24 	imes 3600}}$$
= 63.2 ÃÂ 10
6
watt or 63.2 Mega Watt
$$ \simeq $$ 60 MW

Answer

125 MW

Answer

60 MW

Answer

54 MW

Answer

35 MW

Atoms & Nuclei

In a reactor, 2 kg of 92U235 fuel is fully used up in 30 days. The energy released per fission is 200 MeV. Given that the Avogadro number, N = 6.023 $ \times $ 1026 per kilo mole and 1 eV = 1.6 × 10–19 J. The power output of the reactor is close to

Choose the correct answer: