Question 222: Atoms & Nuclei

Question

A hydrogen atom in its ground state absorbs 10.2 eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of :
(Given, Planck's constant = 6.6 $$	imes$$ 10$$-$$34 Js).

Accepted Answer

$$ - 13.6 + 10.2 = {{ - 13.6} \over {{n^2}}}$$
$$ \Rightarrow {{13.6} \over {{n^2}}} = 3.4$$
$$ \Rightarrow n = 2$$
$$ \Rightarrow \Delta L = 2 	imes {h \over {2\lambda }} - 1 	imes {h \over {2\lambda }}$$
$$ = {h \over {2\lambda }}$$
$$ \Rightarrow \Delta L \simeq 1.05 	imes {10^{ - 34}}$$ Js

Answer

2.10 $$	imes$$ 10$$-$$34 Js

Answer

1.05 $$	imes$$ 10$$-$$34 Js

Answer

3.15 $$	imes$$ 10$$-$$34 Js

Answer

4.2 $$	imes$$ 10$$-$$34 Js

Atoms & Nuclei

A hydrogen atom in its ground state absorbs 10.2 eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of : (Given, Planck's constant = 6.6 $\times 10-$34 Js).

Choose the correct answer: