Question 593: Atoms & Nuclei

Question

The power obtained in a reactor using U235 disintegration is 1000 kW. The mass decay of U235 per hour is

Accepted Answer

From Einstein relation, E = mc
2
Rearranging, m = $${E \over {{c^2}}}$$
We see that mass decay per second :
$${{dm} \over {dt}}$$ = $${1 \over {{c^2}}}$$
 ÃÂ $${{dE} \over {dt}}$$ = $${{1000 	imes {{10}^3}} \over {{{\left( {3 	imes {{10}^8}} ight)}^2}}}$$
Now mass decay of U
235
per hour,
= $${{dm} \over {dt}}$$ $$ 	imes $$ 60 $$ 	imes $$ 60
= $${{1000 	imes {{10}^3}} \over {{{\left( {3 	imes {{10}^8}} ight)}^2}}}$$ $$ 	imes $$ 3600
= 4 ÃÂ 10
Ã¢ÂÂ8
kg = 40 microgram

Answer

10 microgram

Answer

20 microgram

Answer

40 microgram

Answer

1 microgram

Atoms & Nuclei

The power obtained in a reactor using U235 disintegration is 1000 kW. The mass decay of U235 per hour is

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