Question 300: Atoms & Nuclei

Question

Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron = 1.1 MeV and for helium = 7.0 MeV)

Accepted Answer

1
H
2
+
1
H
2
$$ 	o $$
2
He
4
No. of proton in one dueteron = 2
$$	herefore\,\,\,$$ Total protons in two dueterons = 2 $$ 	imes $$ 2 = 4
$$	herefore\,\,\,$$ Binding energy of two dueteron
= 1.1 $$ 	imes $$ 4 = 4 : 4 MeV
In (
2
He
4
) no of protons = 4
$$	herefore\,\,\,$$ Binding energy of (
2
He
4
) nuclei = 4 $$ 	imes $$ 7 = 28 Mev
Energy released in this process = 28 $$-$$ 4.4 = 23.6 MeV

Answer

30.2 MeV

Answer

32.4 MeV

Answer

23.6 MeV

Answer

25.8 MeV

Atoms & Nuclei

Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron = 1.1 MeV and for helium = 7.0 MeV)

Choose the correct answer: