Question 337: Atoms & Nuclei

Question

The binding energy per nucleon of deuteron $$\left( {{}_1^2\,H} \right)$$ and helium nucleus $$\left( {{}_2^4\,He} \right)$$ is $$1.1$$ $$MeV$$ and $$7$$ $$MeV$$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

Accepted Answer

The nuclear reaction of process is $$2_1^2H 	o {4 \over 2}$$ He
Energy released $$ = 4 	imes \left( 7 ight) - 4\left( {1.1} ight) = 23.6\,MeV$$

Answer

$$23.6\,\,MeV$$

Answer

$$26.9\,\,MeV$$

Answer

$$13.9\,\,MeV$$

Answer

$$19.2\,\,MeV$$

Atoms & Nuclei

The binding energy per nucleon of deuteron $\left( {{}_1^2\,H} \right) and helium nucleus \left( {{}_2^4\,He} \right) is 1.1 MeV and 7 MeV$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

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