Question 322: Atoms & Nuclei

Question

The half-life period of a ratio-active element $$X$$ is same as the mean life time of another ratio-active element $$Y.$$ Initially they have the same number of atoms. Then

Accepted Answer

According to question,
Half life of $$X,\,{T_{1/2}} = {	au _{av}},\,\,\,$$ average life of $$Y$$
$$ \Rightarrow {{0.693} \over {{\lambda _X}}} = {1 \over {{\lambda _Y}}} \Rightarrow {\lambda _X} = \left( {0.693} ight).{\lambda _Y}$$
$$	herefore$$ $${\lambda _X} < {\lambda _Y}.$$
Now, the rate of decay is given by
$$ - {{dN} \over {dt}} = \lambda N$$
$$	herefore$$ $$Y$$ will decay faster than $$X.$$ [ as $$N$$ is same ]

Answer

$$X$$ and $$Y$$ decay at same rate always

Answer

$$X$$ will decay faster than $$Y$$

Answer

$$Y$$ will decay faster than $$X$$

Answer

$$X$$ and $$Y$$ have same decay rate initially

Atoms & Nuclei

The half-life period of a ratio-active element $X is same as the mean life time of another ratio-active element Y.$ Initially they have the same number of atoms. Then

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