Question 211: Atoms & Nuclei

Question

Mass numbers of two nuclei are in the ratio of $$4: 3$$. Their nuclear densities will be in the ratio of

Accepted Answer

$$	herefore$$ $$R = {R_0}{A^{{1 \over 3}}}$$
$$ \Rightarrow {{{R_1}} \over {{R_2}}} = {\left( {{{{A_1}} \over {{A_2}}}} ight)^{{1 \over 3}}} = {\left( {{4 \over 3}} ight)^{{1 \over 3}}}$$
$$	herefore$$ Density ratio, $${{{ho _1}} \over {{ho _2}}} = {{{A_1}/{V_1}} \over {{A_2}/{V_2}}}$$
$$ = \left( {{{{A_1}} \over {{A_2}}}} ight) 	imes {\left( {{{{R_2}} \over {{R_1}}}} ight)^3}$$
$$ = 1:1$$

Answer

4 : 3

Answer

$$\left(\frac{3}{4}\right)^{\frac{1}{3}}$$

Answer

1 : 1

Answer

$$\left(\frac{4}{3}\right)^{\frac{1}{3}}$$

Atoms & Nuclei

Mass numbers of two nuclei are in the ratio of $4: 3$. Their nuclear densities will be in the ratio of

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