Question 432: Atoms & Nuclei

Question

$$ \begin{aligned} &	ext { For the following reaction, the particle ' } \mathrm{x} 	ext { ' is }{ }_6 \mathrm{C}^{11}\longrightarrow{ }_5 \mathrm{~B}^{11}+\beta+\mathrm{X} \end{aligned} $$

Accepted Answer

Given reaction is:
$${}_6\mathrm{C}^{11} \longrightarrow {}_5\mathrm{B}^{11} + \beta + X$$
Let's break it down step-by-step:
Identify $\beta$ particle:
A $\beta$ particle in nuclear reactions usually refers to a
beta-minus ($\beta^-$) particle
, which is an electron ($e^-$).
Write nuclear equations:
A general $\beta^-$ decay reaction is:
$${}_Z^A X ightarrow {}_{Z+1}^A Y + \beta^- + \overline{
u}$$
Where:
$X$ is the parent nucleus,
$Y$ is the daughter nucleus,
$\beta^-$ is the emitted electron,
$\overline{
u}$ is the
anti-neutrino
.
Apply to given reaction:
In this reaction:
The atomic number decreases: from $6$ (Carbon) to $5$ (Boron)
This fits
beta-plus ($\beta^+$) decay
, not beta-minus
But the question writes $\beta$ (generic). However, with decrease in atomic number, it should be $\beta^+$ (positron), not $\beta^-$. But let's carry forward with the usual nuclear conventions, where
$${}_Z^A X ightarrow {}_{Z-1}^A Y + \beta^+ + 
u$$
Here, the neutrino ($
u$) is emitted along with the $\beta^+$.
Determine particle 'X'
Comparing with the general reaction:
For
beta-positive
($\beta^+$) decay,
$${}_6^{11}\mathrm{C} ightarrow {}_5^{11}\mathrm{B} + \beta^+ + 
u$$
Thus, $X = 
u =$
neutrino
.
Final Answer:
Option B: neutrino

Answer

proton

Answer

neutrino

Answer

anti neutrino

Answer

neutron

Atoms & Nuclei

\begin{aligned} &\text { For the following reaction, the particle ' } \mathrm{x} \text { ' is }{ }_6 \mathrm{C}^{11}\longrightarrow{ }_5 \mathrm{~B}^{11}+\beta+\mathrm{X} \end{aligned}

Choose the correct answer: