Question 296: Atoms & Nuclei

Question

The energy required to remove the electron from a singly ionized Helium atom is $$2.2$$ times the energies required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is :

Accepted Answer

Energy required to remove e
$$-$$
from singly ionized Helium atom
E
1
= $${{13.6{z^2}} \over {{n^2}}}$$ = $${{13.6 	imes {2^2}} \over {{1^2}}}$$ = 54.4  eV.
Let, E
2
= energy required to remove e
$$-$$
from He $$-$$ atom
$$	herefore\,\,\,\,$$ According to q vertion.
E
1
= 2.2 E
2
$$	herefore\,\,\,\,$$ E
2
= $${{54.4} \over {2.2}}$$ = 24.72 eV
$$	herefore\,\,\,\,$$ Total energy required to ionize Helium atom completely
= (54.4 + 24.72) eV
= 79.12 eV

Answer

$$20$$ $$eV$$

Answer

$$34$$ $$eV$$

Answer

$$79$$ $$eV$$

Answer

$$109$$ $$eV$$

Atoms & Nuclei

The energy required to remove the electron from a singly ionized Helium atom is $2.2$ times the energies required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is :

Choose the correct answer: