Question 577: Atoms & Nuclei

Question

How does the Binding Energy per nucleon vary with the increase in the number of nucleons ?

Accepted Answer

We see that wavelength of Lyman series,
n
f
= 3, n
i
= 4
$${1 \over {{\lambda _L}}} = R\left[ {{1 \over {{3^2}}} - {1 \over {{4^2}}}} ight]$$ = $${{7R} \over {144}}$$
We see that wavelength of Balmer series :
n
f
= 2, n
i
= 3
$${1 \over {{\lambda _B}}} = R\left[ {{1 \over {{2^2}}} - {1 \over {{3^2}}}} ight]$$ = $${{5R} \over {36}}$$
Now ratio of longest wavelengths corresponds to
Lyman and Balmer series:
$${{{\lambda _L}} \over {{\lambda _B}}} = {5 \over {36}} 	imes {{144} \over 7}$$ = $${5 \over {27}}$$

Answer

Decrease continuously with mass number.

Answer

First decreases and then increases with increase in mass number.

Answer

First increases and then decreases with increase in mass number.

Answer

increases continuously with mass number.

Atoms & Nuclei

How does the Binding Energy per nucleon vary with the increase in the number of nucleons ?

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