Question 610: Atoms & Nuclei

Question

Two nuclei have their mass numbers in the ratio of 1 : 3. The ratio of their nuclear densities would be

Accepted Answer

A
1
: A
2
= 1 : 3
Their radii will be in the ratio
$${R_0}A_1^{1/3}$$ : $${R_0}A_2^{1/3}$$ = 1 : 3
1/3
$$ 	herefore $$ $${ho _{{A_1}}}$$ : $${ho _{{A_2}}}$$ = $${{{A_1}} \over {{4 \over 3}\pi R_1^3}}$$ : $${{{A_2}} \over {{4 \over 3}\pi R_2^3}}$$
= $${1 \over {{1^3}}}:{3 \over {{{\left( {{3^{1/3}}} ight)}^3}}}$$
= 1 : 1

Answer

$${\left( 3 \right)^{1/3}}:1$$

Answer

1 : 1

Answer

1 : 3

Answer

3 : 1

Atoms & Nuclei

Two nuclei have their mass numbers in the ratio of 1 : 3. The ratio of their nuclear densities would be

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