Question 201: Atoms & Nuclei

Question

The ratio of the density of oxygen nucleus ($$_8^{16}O$$) and helium nucleus ($$_2^{4}\mathrm{He}$$) is

Accepted Answer

Nuclear density is independent of mass number
As nuclear density $=\frac{\mathrm{Au}}{\frac{4}{3} \pi \mathrm{R}^3}$
Also, $\mathrm{R}=\mathrm{R}_0 \mathrm{~A}^{\frac{1}{3}}$
And $R^3=R_0^3 A$
$\Rightarrow$ Nuclear density $=\frac{\mathrm{Au}}{\frac{4}{3} \pi \mathrm{R}_0^3 \mathrm{~A}}$
Nuclear density $=\frac{3 \mathrm{u}}{4 \pi \mathrm{R}_0^3}$
$\Rightarrow$ Nuclear density is independent of $\mathrm{A}$

Answer

4 : 1

Answer

1 : 1

Answer

2 : 1

Answer

8 : 1

Atoms & Nuclei

The ratio of the density of oxygen nucleus ($_8^{16}O) and helium nucleus (_2^{4}\mathrm{He}$) is

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