Question 193: Dual Nature of Matter and Radiation

Question

An electron (of mass m) and a photon have the same energy E in the range of a few eV. The ratio
of the de-Broglie wavelength associated with the electron and the wavelength of the photon is (c
= speed of light in vaccuum)

Accepted Answer

$$\lambda $$
e
= $${h \over {{p_e}}}$$ = $${h \over {\sqrt {2mE} }}$$
E = $${{hc} \over {{\lambda _{photon}}}}$$
$$ \Rightarrow $$ $${{\lambda _{photon}}}$$ = $${{hc} \over E}$$
$$ 	herefore $$ $${{{\lambda _e}} \over {{\lambda _{photon}}}}$$ = $${1 \over c}{\left( {{E \over {2m}}} ight)^{{1 \over 2}}}$$

Answer

$${1 \over c}{\left( {{{2E} \over m}} \right)^{{1 \over 2}}}$$

Answer

$${1 \over c}{\left( {{E \over {2m}}} \right)^{{1 \over 2}}}$$

Answer

$${\left( {{E \over {2m}}} \right)^{{1 \over 2}}}$$

Answer

$$c{\left( {2mE} \right)^{{1 \over 2}}}$$

Dual Nature of Matter and Radiation

An electron (of mass m) and a photon have the same energy E in the range of a few eV. The ratio of the de-Broglie wavelength associated with the electron and the wavelength of the photon is (c = speed of light in vaccuum)

Choose the correct answer: