Question 189: Dual Nature of Matter and Radiation

Question

A particle moving with kinetic energy E has
de Broglie wavelength $$\lambda $$. If energy $$\Delta $$E is added
to its energy, the wavelength become $$\lambda $$/2. Value
of $$\Delta $$E, is :

Accepted Answer

$$\lambda  = {h \over {\sqrt {2mE} }}$$
Also, $${h \over {\sqrt {2m\left( {E + \Delta E} ight)} }}$$ = $${\lambda  \over 2}$$
$$ 	herefore $$ $${{E + \Delta E} \over E} = 4$$
$$ \Rightarrow $$ $$\Delta $$E = 3E

Answer

E

Answer

3E

Answer

2E

Answer

4E

Dual Nature of Matter and Radiation

A particle moving with kinetic energy E has de Broglie wavelength $\lambda . If energy \Delta E is added to its energy, the wavelength become \lambda /2. Value of \Delta $E, is :

Choose the correct answer: