Question 26: Dual Nature of Matter and Radiation

Question

The velocity of the proton is one-fourth the velocity of the electron. What is the ratio of the de-Broglie wavelength of an electron to that of a proton?

Accepted Answer

The de-Broglie wavelength is given by
$$\lambda  = {h \over p} = {h \over {mv}}$$
$$ \Rightarrow {{{\lambda _e}} \over {{\lambda _p}}} = {{{h \over {m{v_e}}}} \over {{h \over {m{v_p}}}}} = {{{v_p}} \over {{v_e}}} = {{{{{v_e}} \over 4}} \over {{v_e}}} = {1 \over 4}$$ ($$	herefore$$ $${v_p} = {1 \over 4} 	imes {v_e}$$)

Answer

$$1$$

Answer

$$\frac{1}{2}$$

Answer

$$\frac{1}{3}$$

Answer

$$\frac{1}{4}$$

Dual Nature of Matter and Radiation

The velocity of the proton is one-fourth the velocity of the electron. What is the ratio of the de-Broglie wavelength of an electron to that of a proton?

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