Question 321: Dual Nature of Matter and Radiation

Question

The stopping potential for a photelectric emission process is 10 V . The maximum kinetic energy of the electrons ejected in the process is [Charge on electron $\mathrm{e}=1.6 	imes 10^{-19} \mathrm{C}$ ]

Accepted Answer

Maximum kinetic energy is given by,
$$\begin{aligned}
& (	ext { K.E. })_{\max }=\mathrm{eV}_{\mathrm{s}} \
& 	ext { (K.E. })_{\max }=\left(1.6 	imes 10^{-19}ight) 	imes 10 \quad \ldots\left(	ext { given, } \mathrm{V}_{\mathrm{s}}=10 \mathrm{~V}ight)
\end{aligned}$$
$$	herefore\quad	ext { (K.E. })_{\max }=1.6 	imes 10^{-18} \mathrm{~J}
$$

Answer

$3.2 	imes 10^{-19} \mathrm{~J}$

Answer

$1.6 	imes 10^{-19} \mathrm{~J}$

Answer

$1.6 	imes 10^{-18} \mathrm{~J}$

Answer

0 J

Dual Nature of Matter and Radiation

The stopping potential for a photelectric emission process is 10 V . The maximum kinetic energy of the electrons ejected in the process is [Charge on electron \mathrm{e}=1.6 \times 10^{-19} \mathrm{C} ]

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