Question 183: Dual Nature of Matter and Radiation

Question

Given figure shows few data points in a phot electric effect experiment for a certain metal. The
minimum energy for ejection of electron from its surface is: (Plancks constant h = 6.62 × 10–34 J.s)

Accepted Answer

K
max
= hf - $$\phi $$
$$ \Rightarrow $$ eV
0
= hf - $$\phi $$
at B V
0
= 0,  f = 5.5
$$ 	herefore $$ $$\phi $$ = hf
= $${6.62 	imes {{10}^{ - 34}} 	imes 5.5 	imes {{10}^{14}}}$$ J
= $${{6.62 	imes {{10}^{ - 34}} 	imes 5.5 	imes {{10}^{14}}} \over {1.6 	imes {{10}^{ - 19}}}}$$ eV
= 2.27 eV

Answer

2.10 eV

Answer

2.27 eV

Answer

2.59 eV

Answer

1.93 eV

Dual Nature of Matter and Radiation

Given figure shows few data points in a phot electric effect experiment for a certain metal. The minimum energy for ejection of electron from its surface is: (Plancks constant h = 6.62 × 10–34 J.s)

Choose the correct answer: