Question 161: Dual Nature of Matter and Radiation

Question

What should be the order of arrangement of de-Broglie wavelength of electron ($$\lambda$$e), an $$\alpha$$-particle ($$\lambda$$a) and proton ($$\lambda$$p) given that all have the same kinetic energy?

Accepted Answer

$$\lambda  = {h \over p} = {h \over {\sqrt {2mE} }} \propto {1 \over {\sqrt m }}$$
m
$$\alpha$$
> m
p
> m
e
So, $$\lambda$$
e
> $$\lambda$$
p
> $$\lambda$$
$$\alpha$$

Answer

$$\lambda$$e = $$\lambda$$p = $$\lambda$$$$\alpha$$

Answer

$$\lambda$$e < $$\lambda$$p < $$\lambda$$$$\alpha$$

Answer

$$\lambda$$e > $$\lambda$$p > $$\lambda$$$$\alpha$$

Answer

$$\lambda$$e = $$\lambda$$p > $$\lambda$$$$\alpha$$

Dual Nature of Matter and Radiation

What should be the order of arrangement of de-Broglie wavelength of electron ($\lambdae), an \alpha-particle (\lambdaa) and proton (\lambda$p) given that all have the same kinetic energy?

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