Question 347: Dual Nature of Matter and Radiation

Question

A photon has wavelength $$3 \mathrm{~nm}$$, then its momentum and energy respectively will be $$[\mathrm{h}=6.63 	imes 10^{-34} \mathrm{Js}, \mathrm{c}=$$ velocity of light $$=3 	imes 10^8 \mathrm{~m} / \mathrm{s}]$$

Accepted Answer

Momentum $$\mathrm{p}=\frac{\mathrm{h}}{\lambda}=\frac{6.63 	imes 10^{-34}}{3 	imes 10^{-9}}=2.21 	imes 10^{-25} \mathrm{~kg} \mathrm{~ms}^{-1}$$
Energy
$$\begin{aligned}
E & =\frac{h c}{\lambda}=p c=2.21 	imes 10^{-25} 	imes 3 	imes 10^8 \
& =6.63 	imes 10^{-17} \mathrm{~J}
\end{aligned}$$

Answer

$$2.21 	imes 10^{-43} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 	imes 10^{-34} \mathrm{~J}$$

Answer

$$2.21 	imes 10^{-34} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 	imes 10^{-25} \mathrm{~J}$$

Answer

$$2.21 	imes 10^{-25} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 	imes 10^{-17} \mathrm{~J}$$

Answer

$$2.21 	imes 10^{-16} \mathrm{~kg} \mathrm{~ms}^{-1} ; 6.63 	imes 10^{-19} \mathrm{~J}$$

Dual Nature of Matter and Radiation

A photon has wavelength $3 \mathrm{~nm}, then its momentum and energy respectively will be [\mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}, \mathrm{c}= velocity of light =3 \times 10^8 \mathrm{~m} / \mathrm{s}]

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