Question 302: Dual Nature of Matter and Radiation

Question

If the potential difference used to accelerate electrons is doubled. By what factor does the deBroglie wavelength $(\lambda)$ associated with the electrons change?

Accepted Answer

From $\lambda=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mqV}}}$,
$\lambda \propto \frac{1}{\sqrt{v}}$
If potential difference is doubled,
$\lambda \propto \frac{1}{\sqrt{2 \mathrm{~V}}}$
$	herefore \quad \lambda$ is decreased by $\frac{1}{\sqrt{2}}$ times.

Answer

$\lambda$ is increased to $\sqrt{2}$ times.

Answer

$\lambda$ is increased to $\frac{1}{\sqrt{2}}$ times.

Answer

$\lambda$ is decreased to $\frac{1}{\sqrt{2}}$ times.

Answer

$\lambda$ is decreased to $\sqrt{2}$ times.

Dual Nature of Matter and Radiation

If the potential difference used to accelerate electrons is doubled. By what factor does the deBroglie wavelength (\lambda) associated with the electrons change?

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