Question 151: Waves Optics

Question

In a Young's double slit experiment, the path difference, at a certain point on the screen, between two interfering waves is $${1 \over 8}$$ th of wavelength. The ratio of the intensity at this point to that at the centre of a bright fringe is close to :

Accepted Answer

$$\Delta $$x $$=$$ $${\lambda  \over 8}$$
$$\Delta $$$$\phi $$ $$=$$ $${{\left( {2\pi } \right)} \over \lambda }{\lambda  \over 8} = {\pi  \over 4}$$
I $$=$$ I
0
cos
2
$$\left( {{\pi  \over 8}} \right)$$
$${{\rm I} \over {{{\rm I}_0}}} = $$ cos
2
$$\left( {{\pi  \over 8}} \right)$$

Answer

0.94

Answer

0.85

Answer

0.74

Answer

0.80

Waves Optics

In a Young's double slit experiment, the path difference, at a certain point on the screen, between two interfering waves is ${1 \over 8}$ th of wavelength. The ratio of the intensity at this point to that at the centre of a bright fringe is close to :

Choose the correct answer: