Question 126: Waves Optics

Question

In a Young's double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be :

Accepted Answer

Fringe width ($$\beta$$) = $${{\lambda D} \over d}$$
d = 2 $$	imes$$ 10
$$-$$3
m
$$\lambda$$ = 500 $$	imes$$ 10
$$-$$9
m
D = 1 m
Now
$$\beta$$ = $${{500 	imes {{10}^{ - 9}} 	imes 1} \over {2 	imes {{10}^{ - 3}}}}$$
$$\beta$$ = $${5 \over 2} 	imes {10^{ - 4}}$$
$$\beta$$ = 2.5 $$	imes$$ 10
$$-$$4
$$\beta$$ = 0.25 mm

Answer

0.50 mm

Answer

0.25 mm

Answer

1 mm

Answer

0.75 mm

Waves Optics

In a Young's double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be :

Choose the correct answer: