Question 280: Waves Optics

Question

Sodium light $\left(\lambda=6 	imes 10^{-7} \mathrm{~m}ight)$ is used to produce interference pattern. The observed fringe width is 0.12 mm . The angle between the two wave trains is

Accepted Answer

To determine the angle between the two wave trains when sodium light is used, we can start with the formula for fringe width in an interference pattern:
$ W = \frac{\lambda D}{d} $
Here, $ \lambda = 6 	imes 10^{-7} \, 	ext{m} $ is the wavelength of sodium light, and $ W = 0.12 \, 	ext{mm} = 0.12 	imes 10^{-3} \, 	ext{m} $ is the observed fringe width.
To find the angle between the two wave trains, we use the relationship:
$ \frac{d}{D} = \frac{\lambda}{W} $
The calculations are as follows:
$ \frac{d}{D} = \frac{6 	imes 10^{-7}}{0.12 	imes 10^{-3}} $
$ \frac{d}{D} = 5 	imes 10^{-3} \, 	ext{rad} $
Thus, the angle between the two wave trains is $ 5 	imes 10^{-3} \, 	ext{rad} $.

Answer

$5 	imes 10^{-1} \mathrm{rad}$

Answer

$5 	imes 10^{-3} \mathrm{rad}$

Answer

$1 	imes 10^{-2} \mathrm{rad}$

Answer

$1 	imes 10^{-3} \mathrm{rad}$

Waves Optics

Sodium light \left(\lambda=6 \times 10^{-7} \mathrm{~m}\right) is used to produce interference pattern. The observed fringe width is 0.12 mm . The angle between the two wave trains is

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