Question 183: Waves Optics

Question

The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young's double-slit experiment, is :

Accepted Answer

For constructive interference $$d\,\sin 	heta  = n\lambda $$
Given $$d = 2\lambda  \Rightarrow \sin 	heta  = {n \over 2}$$
$$n = 0,1, - 1,2, - 2$$ hence five maxima are possible.

Answer

three

Answer

five

Answer

infinite

Answer

zero

Waves Optics

The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young's double-slit experiment, is :

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