Question 385: Waves Optics

Question

A light wave of wavelength $$\lambda$$ is incident on a slit of width $$d$$. The resulting diffraction pattern is observed on a screen at a distance $$D$$. If linear width of the principal maxima is equal to the width of the slit, then the distance $$D$$ is

Accepted Answer

The linear width of the principal maxima in a diffraction pattern is given by:
$ \beta = \frac{2 D \lambda}{d} $
It is stated that the linear width of the principal maxima is equal to the width of the slit. Therefore, we have:
$ d = \frac{2 D \lambda}{d} $
Solving for $D$, we can rearrange the equation to find:
$ D = \frac{d^2}{2 \lambda} $

Answer

$$\frac{2 \lambda}{d}$$

Answer

$$\frac{d^2}{2 \lambda}$$

Answer

$$\frac{2 \lambda^2}{d}$$

Answer

$$\frac{d}{\lambda}$$

Waves Optics

A light wave of wavelength $\lambda is incident on a slit of width d. The resulting diffraction pattern is observed on a screen at a distance D. If linear width of the principal maxima is equal to the width of the slit, then the distance D$ is

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