Question 423: Waves Optics

Question

In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern ?

Accepted Answer

Fringe width, $$\beta $$ = $${{D\lambda } \over d}$$
As per question, width of central maxima of single slit pattern = width of 10 maxima of double slit pattern
$${{D2\lambda } \over a} = 10\left( {{{\lambda D} \over d}} ight)$$
$$ \Rightarrow $$ $$a$$ = $${{2d} \over {10}}$$ = $${{2 	imes {{10}^{ - 3}}} \over {10}}$$ = 0.2 $$ 	imes $$ 10
-3
m =  0.2 mm

Answer

0.5 mm

Answer

0.02 mm

Answer

0.2 mm

Answer

0.1 mm

Waves Optics

In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern ?

Choose the correct answer: